Prompt Title: Sinkhorn

Created 1 year ago
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Yes, you can calculate the Wasserstein distance in PyTorch and use it as an optimizable loss function. Here, we'll use the Sinkhorn algorithm for an approximate computation of the Wasserstein distance, which is differentiable and suitable for gradient-based optimization. We'll implement the Sinkhorn algorithm using PyTorch and use it as a loss function for a toy example.

  1. Implement Sinkhorn algorithm in PyTorch:
python
import torch def sinkhorn_loss(x, y, epsilon=0.1, max_iter=50): """ Compute the Sinkhorn loss (approximate Wasserstein distance) between two sets of points x and y. Args: x (torch.Tensor): First set of points (batch_size x n x dim). y (torch.Tensor): Second set of points (batch_size x m x dim). epsilon (float): Entropic regularization parameter. max_iter (int): Maximum number of Sinkhorn iterations. Returns: torch.Tensor: Sinkhorn loss (batch_size). """ batch_size, n, dim = x.shape _, m, _ = y.shape # Compute pairwise distance matrix x = x.view(batch_size, n, 1, dim) y = y.view(batch_size, 1, m, dim) M = torch.sum((x - y) ** 2, dim=-1) # Pairwise squared Euclidean distances # Initialize Sinkhorn iteration K = torch.exp(-M / epsilon) u = torch.ones(batch_size, n) / n v = torch.ones(batch_size, m) / m # Sinkhorn iteration for _ in range(max_iter): u = 1.0 / torch.matmul(K, v) v = 1.0 / torch.matmul(K.transpose(1, 2), u) # Sinkhorn loss loss = torch.sum(u.view(batch_size, n, 1) * K * v.view(batch_size, 1, m) * M, dim=[1, 2]) return loss
  1. Use Sinkhorn loss as an optimizable loss function:

Here's a toy example where we try to match the distribution of two sets of 2D points using gradient descent:

python
import torch.optim as optim # Create two sets of points x = torch.tensor([[1.0, 1.0], [2.0, 2.0], [3.0, 3.0]]) y = torch.tensor([[3.0, 3.0], [4.0, 4.0], [5.0, 5.0]]) x.requires_grad_(True) # Create an optimizer optimizer = optim.SGD([x], lr=0.01) # Optimize num_epochs = 500 for epoch in range(num_epochs): optimizer.zero_grad() loss = sinkhorn_loss(x.unsqueeze(0), y.unsqueeze(0)) loss.backward() optimizer.step() if (epoch + 1) % 50 == 0: print(f"Epoch [{epoch + 1}/{num_epochs}], Loss: {loss.item()}")

In this example, we first create two sets of points x and y, then optimize x using gradient descent to minimize the Sinkhorn loss (approximate Wasserstein distance) between x and y. The Sinkhorn loss is differentiable, allowing the optimization to be performed using standard gradient-based techniques.

Please note that this is a toy example for illustration purposes. In real-world applications, you would use the Sinkhorn loss

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yi zeng
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Created 1 year ago

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